3.13.16 \(\int \frac {(a+a \sec (c+d x))^4 (A+B \sec (c+d x)+C \sec ^2(c+d x))}{\sqrt {\cos (c+d x)}} \, dx\) [1216]

3.13.16.1 Optimal result
3.13.16.2 Mathematica [C] (warning: unable to verify)
3.13.16.3 Rubi [A] (verified)
3.13.16.4 Maple [B] (verified)
3.13.16.5 Fricas [C] (verification not implemented)
3.13.16.6 Sympy [F(-1)]
3.13.16.7 Maxima [F(-1)]
3.13.16.8 Giac [F]
3.13.16.9 Mupad [B] (verification not implemented)

3.13.16.1 Optimal result

Integrand size = 43, antiderivative size = 310 \[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx=-\frac {8 a^4 (24 A+19 B+16 C) E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{15 d}+\frac {8 a^4 (187 A+132 B+113 C) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{231 d}+\frac {4 a^4 (913 A+803 B+667 C) \sin (c+d x)}{1155 d \cos ^{\frac {3}{2}}(c+d x)}+\frac {8 a^4 (24 A+19 B+16 C) \sin (c+d x)}{15 d \sqrt {\cos (c+d x)}}+\frac {2 a (11 B+8 C) (a+a \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac {9}{2}}(c+d x)}+\frac {2 C (a+a \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac {11}{2}}(c+d x)}+\frac {2 (33 A+55 B+43 C) \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{231 d \cos ^{\frac {7}{2}}(c+d x)}+\frac {4 (891 A+946 B+769 C) \left (a^4+a^4 \cos (c+d x)\right ) \sin (c+d x)}{3465 d \cos ^{\frac {5}{2}}(c+d x)} \]

output
-8/15*a^4*(24*A+19*B+16*C)*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c) 
*EllipticE(sin(1/2*d*x+1/2*c),2^(1/2))/d+8/231*a^4*(187*A+132*B+113*C)*(co 
s(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticF(sin(1/2*d*x+1/2*c), 
2^(1/2))/d+4/1155*a^4*(913*A+803*B+667*C)*sin(d*x+c)/d/cos(d*x+c)^(3/2)+2/ 
99*a*(11*B+8*C)*(a+a*cos(d*x+c))^3*sin(d*x+c)/d/cos(d*x+c)^(9/2)+2/11*C*(a 
+a*cos(d*x+c))^4*sin(d*x+c)/d/cos(d*x+c)^(11/2)+2/231*(33*A+55*B+43*C)*(a^ 
2+a^2*cos(d*x+c))^2*sin(d*x+c)/d/cos(d*x+c)^(7/2)+4/3465*(891*A+946*B+769* 
C)*(a^4+a^4*cos(d*x+c))*sin(d*x+c)/d/cos(d*x+c)^(5/2)+8/15*a^4*(24*A+19*B+ 
16*C)*sin(d*x+c)/d/cos(d*x+c)^(1/2)
 
3.13.16.2 Mathematica [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 14.22 (sec) , antiderivative size = 1795, normalized size of antiderivative = 5.79 \[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx =\text {Too large to display} \]

input
Integrate[((a + a*Sec[c + d*x])^4*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2)) 
/Sqrt[Cos[c + d*x]],x]
 
output
(Cos[c + d*x]^(13/2)*Sec[c/2 + (d*x)/2]^8*(a + a*Sec[c + d*x])^4*(A + B*Se 
c[c + d*x] + C*Sec[c + d*x]^2)*(((24*A + 19*B + 16*C)*Csc[c]*Sec[c])/(15*d 
) + (C*Sec[c]*Sec[c + d*x]^6*Sin[d*x])/(44*d) + (Sec[c]*Sec[c + d*x]^5*(9* 
C*Sin[c] + 11*B*Sin[d*x] + 44*C*Sin[d*x]))/(396*d) + (Sec[c]*Sec[c + d*x]^ 
4*(77*B*Sin[c] + 308*C*Sin[c] + 99*A*Sin[d*x] + 396*B*Sin[d*x] + 675*C*Sin 
[d*x]))/(2772*d) + (Sec[c]*Sec[c + d*x]^3*(495*A*Sin[c] + 1980*B*Sin[c] + 
3375*C*Sin[c] + 2772*A*Sin[d*x] + 4697*B*Sin[d*x] + 4928*C*Sin[d*x]))/(138 
60*d) + (Sec[c]*Sec[c + d*x]*(2585*A*Sin[c] + 2640*B*Sin[c] + 2260*C*Sin[c 
] + 7392*A*Sin[d*x] + 5852*B*Sin[d*x] + 4928*C*Sin[d*x]))/(4620*d) + (Sec[ 
c]*Sec[c + d*x]^2*(2772*A*Sin[c] + 4697*B*Sin[c] + 4928*C*Sin[c] + 7755*A* 
Sin[d*x] + 7920*B*Sin[d*x] + 6780*C*Sin[d*x]))/(13860*d)))/(A + 2*C + 2*B* 
Cos[c + d*x] + A*Cos[2*c + 2*d*x]) - (17*A*Cos[c + d*x]^6*Csc[c]*Hypergeom 
etricPFQ[{1/4, 1/2}, {5/4}, Sin[d*x - ArcTan[Cot[c]]]^2]*Sec[c/2 + (d*x)/2 
]^8*(a + a*Sec[c + d*x])^4*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2)*Sec[d*x 
 - ArcTan[Cot[c]]]*Sqrt[1 - Sin[d*x - ArcTan[Cot[c]]]]*Sqrt[-(Sqrt[1 + Cot 
[c]^2]*Sin[c]*Sin[d*x - ArcTan[Cot[c]]])]*Sqrt[1 + Sin[d*x - ArcTan[Cot[c] 
]]])/(21*d*(A + 2*C + 2*B*Cos[c + d*x] + A*Cos[2*c + 2*d*x])*Sqrt[1 + Cot[ 
c]^2]) - (4*B*Cos[c + d*x]^6*Csc[c]*HypergeometricPFQ[{1/4, 1/2}, {5/4}, S 
in[d*x - ArcTan[Cot[c]]]^2]*Sec[c/2 + (d*x)/2]^8*(a + a*Sec[c + d*x])^4*(A 
 + B*Sec[c + d*x] + C*Sec[c + d*x]^2)*Sec[d*x - ArcTan[Cot[c]]]*Sqrt[1 ...
 
3.13.16.3 Rubi [A] (verified)

Time = 2.24 (sec) , antiderivative size = 319, normalized size of antiderivative = 1.03, number of steps used = 25, number of rules used = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.581, Rules used = {3042, 4600, 3042, 3522, 27, 3042, 3454, 27, 3042, 3454, 3042, 3454, 27, 3042, 3447, 3042, 3500, 27, 3042, 3227, 3042, 3116, 3042, 3119, 3120}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(a \sec (c+d x)+a)^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(a \sec (c+d x)+a)^4 \left (A+B \sec (c+d x)+C \sec (c+d x)^2\right )}{\sqrt {\cos (c+d x)}}dx\)

\(\Big \downarrow \) 4600

\(\displaystyle \int \frac {(a \cos (c+d x)+a)^4 \left (A \cos ^2(c+d x)+B \cos (c+d x)+C\right )}{\cos ^{\frac {13}{2}}(c+d x)}dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\left (a \sin \left (c+d x+\frac {\pi }{2}\right )+a\right )^4 \left (A \sin \left (c+d x+\frac {\pi }{2}\right )^2+B \sin \left (c+d x+\frac {\pi }{2}\right )+C\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{13/2}}dx\)

\(\Big \downarrow \) 3522

\(\displaystyle \frac {2 \int \frac {(\cos (c+d x) a+a)^4 (a (11 B+8 C)+a (11 A+C) \cos (c+d x))}{2 \cos ^{\frac {11}{2}}(c+d x)}dx}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {(\cos (c+d x) a+a)^4 (a (11 B+8 C)+a (11 A+C) \cos (c+d x))}{\cos ^{\frac {11}{2}}(c+d x)}dx}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^4 \left (a (11 B+8 C)+a (11 A+C) \sin \left (c+d x+\frac {\pi }{2}\right )\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{11/2}}dx}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3454

\(\displaystyle \frac {\frac {2}{9} \int \frac {(\cos (c+d x) a+a)^3 \left (3 (33 A+55 B+43 C) a^2+(99 A+11 B+17 C) \cos (c+d x) a^2\right )}{2 \cos ^{\frac {9}{2}}(c+d x)}dx+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {1}{9} \int \frac {(\cos (c+d x) a+a)^3 \left (3 (33 A+55 B+43 C) a^2+(99 A+11 B+17 C) \cos (c+d x) a^2\right )}{\cos ^{\frac {9}{2}}(c+d x)}dx+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^3 \left (3 (33 A+55 B+43 C) a^2+(99 A+11 B+17 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^2\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{9/2}}dx+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3454

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \int \frac {(\cos (c+d x) a+a)^2 \left ((891 A+946 B+769 C) a^3+(396 A+121 B+124 C) \cos (c+d x) a^3\right )}{\cos ^{\frac {7}{2}}(c+d x)}dx+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^2 \left ((891 A+946 B+769 C) a^3+(396 A+121 B+124 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^3\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{7/2}}dx+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3454

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {2}{5} \int \frac {3 (\cos (c+d x) a+a) \left (3 (913 A+803 B+667 C) a^4+(957 A+517 B+463 C) \cos (c+d x) a^4\right )}{2 \cos ^{\frac {5}{2}}(c+d x)}dx+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \int \frac {(\cos (c+d x) a+a) \left (3 (913 A+803 B+667 C) a^4+(957 A+517 B+463 C) \cos (c+d x) a^4\right )}{\cos ^{\frac {5}{2}}(c+d x)}dx+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right ) \left (3 (913 A+803 B+667 C) a^4+(957 A+517 B+463 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^4\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{5/2}}dx+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3447

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \int \frac {(957 A+517 B+463 C) \cos ^2(c+d x) a^5+3 (913 A+803 B+667 C) a^5+\left ((957 A+517 B+463 C) a^5+3 (913 A+803 B+667 C) a^5\right ) \cos (c+d x)}{\cos ^{\frac {5}{2}}(c+d x)}dx+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \int \frac {(957 A+517 B+463 C) \sin \left (c+d x+\frac {\pi }{2}\right )^2 a^5+3 (913 A+803 B+667 C) a^5+\left ((957 A+517 B+463 C) a^5+3 (913 A+803 B+667 C) a^5\right ) \sin \left (c+d x+\frac {\pi }{2}\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^{5/2}}dx+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3500

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (\frac {2}{3} \int \frac {3 \left (77 (24 A+19 B+16 C) a^5+5 (187 A+132 B+113 C) \cos (c+d x) a^5\right )}{\cos ^{\frac {3}{2}}(c+d x)}dx+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \int \frac {77 (24 A+19 B+16 C) a^5+5 (187 A+132 B+113 C) \cos (c+d x) a^5}{\cos ^{\frac {3}{2}}(c+d x)}dx+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \int \frac {77 (24 A+19 B+16 C) a^5+5 (187 A+132 B+113 C) \sin \left (c+d x+\frac {\pi }{2}\right ) a^5}{\sin \left (c+d x+\frac {\pi }{2}\right )^{3/2}}dx+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3227

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \left (77 a^5 (24 A+19 B+16 C) \int \frac {1}{\cos ^{\frac {3}{2}}(c+d x)}dx+5 a^5 (187 A+132 B+113 C) \int \frac {1}{\sqrt {\cos (c+d x)}}dx\right )+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \left (77 a^5 (24 A+19 B+16 C) \int \frac {1}{\sin \left (c+d x+\frac {\pi }{2}\right )^{3/2}}dx+5 a^5 (187 A+132 B+113 C) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx\right )+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3116

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \left (5 a^5 (187 A+132 B+113 C) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx+77 a^5 (24 A+19 B+16 C) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\int \sqrt {\cos (c+d x)}dx\right )\right )+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \left (5 a^5 (187 A+132 B+113 C) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx+77 a^5 (24 A+19 B+16 C) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\int \sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}dx\right )\right )+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3119

\(\displaystyle \frac {\frac {1}{9} \left (\frac {2}{7} \left (\frac {3}{5} \left (2 \left (5 a^5 (187 A+132 B+113 C) \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx+77 a^5 (24 A+19 B+16 C) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\frac {2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d}\right )\right )+\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}\right )+\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )+\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

\(\Big \downarrow \) 3120

\(\displaystyle \frac {\frac {2 a^2 (11 B+8 C) \sin (c+d x) (a \cos (c+d x)+a)^3}{9 d \cos ^{\frac {9}{2}}(c+d x)}+\frac {1}{9} \left (\frac {2}{7} \left (\frac {2 (891 A+946 B+769 C) \sin (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{5 d \cos ^{\frac {5}{2}}(c+d x)}+\frac {3}{5} \left (\frac {2 a^5 (913 A+803 B+667 C) \sin (c+d x)}{d \cos ^{\frac {3}{2}}(c+d x)}+2 \left (\frac {10 a^5 (187 A+132 B+113 C) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{d}+77 a^5 (24 A+19 B+16 C) \left (\frac {2 \sin (c+d x)}{d \sqrt {\cos (c+d x)}}-\frac {2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d}\right )\right )\right )\right )+\frac {6 a^3 (33 A+55 B+43 C) \sin (c+d x) (a \cos (c+d x)+a)^2}{7 d \cos ^{\frac {7}{2}}(c+d x)}\right )}{11 a}+\frac {2 C \sin (c+d x) (a \cos (c+d x)+a)^4}{11 d \cos ^{\frac {11}{2}}(c+d x)}\)

input
Int[((a + a*Sec[c + d*x])^4*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2))/Sqrt[ 
Cos[c + d*x]],x]
 
output
(2*C*(a + a*Cos[c + d*x])^4*Sin[c + d*x])/(11*d*Cos[c + d*x]^(11/2)) + ((2 
*a^2*(11*B + 8*C)*(a + a*Cos[c + d*x])^3*Sin[c + d*x])/(9*d*Cos[c + d*x]^( 
9/2)) + ((6*a^3*(33*A + 55*B + 43*C)*(a + a*Cos[c + d*x])^2*Sin[c + d*x])/ 
(7*d*Cos[c + d*x]^(7/2)) + (2*((2*(891*A + 946*B + 769*C)*(a^5 + a^5*Cos[c 
 + d*x])*Sin[c + d*x])/(5*d*Cos[c + d*x]^(5/2)) + (3*((2*a^5*(913*A + 803* 
B + 667*C)*Sin[c + d*x])/(d*Cos[c + d*x]^(3/2)) + 2*((10*a^5*(187*A + 132* 
B + 113*C)*EllipticF[(c + d*x)/2, 2])/d + 77*a^5*(24*A + 19*B + 16*C)*((-2 
*EllipticE[(c + d*x)/2, 2])/d + (2*Sin[c + d*x])/(d*Sqrt[Cos[c + d*x]])))) 
)/5))/7)/9)/(11*a)
 

3.13.16.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3116
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*(( 
b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1))), x] + Simp[(n + 2)/(b^2*(n + 1))   I 
nt[(b*Sin[c + d*x])^(n + 2), x], x] /; FreeQ[{b, c, d}, x] && LtQ[n, -1] && 
 IntegerQ[2*n]
 

rule 3119
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* 
(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3120
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 
)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3227
Int[((b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x 
_)]), x_Symbol] :> Simp[c   Int[(b*Sin[e + f*x])^m, x], x] + Simp[d/b   Int 
[(b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{b, c, d, e, f, m}, x]
 

rule 3447
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) 
+ (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Int[(a 
 + b*Sin[e + f*x])^m*(A*c + (B*c + A*d)*Sin[e + f*x] + B*d*Sin[e + f*x]^2), 
 x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0]
 

rule 3454
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + 
(f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Sim 
p[(-b^2)*(B*c - A*d)*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[ 
e + f*x])^(n + 1)/(d*f*(n + 1)*(b*c + a*d))), x] - Simp[b/(d*(n + 1)*(b*c + 
 a*d))   Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])^(n + 1)*Simp 
[a*A*d*(m - n - 2) - B*(a*c*(m - 1) + b*d*(n + 1)) - (A*b*d*(m + n + 1) - B 
*(b*c*m - a*d*(n + 1)))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f 
, A, B}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] 
&& GtQ[m, 1/2] && LtQ[n, -1] && IntegerQ[2*m] && (IntegerQ[2*n] || EqQ[c, 0 
])
 

rule 3500
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + 
 (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(A*b^2 
 - a*b*B + a^2*C))*Cos[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 1)* 
(a^2 - b^2))), x] + Simp[1/(b*(m + 1)*(a^2 - b^2))   Int[(a + b*Sin[e + f*x 
])^(m + 1)*Simp[b*(a*A - b*B + a*C)*(m + 1) - (A*b^2 - a*b*B + a^2*C + b*(A 
*b - a*B + b*C)*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, 
B, C}, x] && LtQ[m, -1] && NeQ[a^2 - b^2, 0]
 

rule 3522
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) 
 + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(c^2*C - B*c*d + A*d^2))*Cos[e + f*x 
]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - 
d^2))), x] + Simp[1/(b*d*(n + 1)*(c^2 - d^2))   Int[(a + b*Sin[e + f*x])^m* 
(c + d*Sin[e + f*x])^(n + 1)*Simp[A*d*(a*d*m + b*c*(n + 1)) + (c*C - B*d)*( 
a*c*m + b*d*(n + 1)) + b*(d*(B*c - A*d)*(m + n + 2) - C*(c^2*(m + 1) + d^2* 
(n + 1)))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, m}, 
 x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !LtQ 
[m, -2^(-1)] && (LtQ[n, -1] || EqQ[m + n + 2, 0])
 

rule 4600
Int[(cos[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*((a_) + (b_.)*sec[(e_.) + (f_.)*(x 
_)])^(m_.)*((A_.) + (B_.)*sec[(e_.) + (f_.)*(x_)] + (C_.)*sec[(e_.) + (f_.) 
*(x_)]^2), x_Symbol] :> Simp[d^(m + 2)   Int[(b + a*Cos[e + f*x])^m*(d*Cos[ 
e + f*x])^(n - m - 2)*(C + B*Cos[e + f*x] + A*Cos[e + f*x]^2), x], x] /; Fr 
eeQ[{a, b, d, e, f, A, B, C, n}, x] &&  !IntegerQ[n] && IntegerQ[m]
 
3.13.16.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1477\) vs. \(2(334)=668\).

Time = 7.51 (sec) , antiderivative size = 1478, normalized size of antiderivative = 4.77

method result size
default \(\text {Expression too large to display}\) \(1478\)

input
int((a+a*sec(d*x+c))^4*(A+B*sec(d*x+c)+C*sec(d*x+c)^2)/cos(d*x+c)^(1/2),x, 
method=_RETURNVERBOSE)
 
output
-32*(-(-2*cos(1/2*d*x+1/2*c)^2+1)*sin(1/2*d*x+1/2*c)^2)^(1/2)*a^4*(1/16*A* 
(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*cos(1/2*d*x+1/2*c)^2+1)^(1/2)/(-2*sin(1/2 
*d*x+1/2*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),2^( 
1/2))+1/16*C*(-1/352*cos(1/2*d*x+1/2*c)*(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d 
*x+1/2*c)^2)^(1/2)/(cos(1/2*d*x+1/2*c)^2-1/2)^6-9/616*cos(1/2*d*x+1/2*c)*( 
-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/2)/(cos(1/2*d*x+1/2*c)^2- 
1/2)^4-15/154*cos(1/2*d*x+1/2*c)*(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1/2* 
c)^2)^(1/2)/(cos(1/2*d*x+1/2*c)^2-1/2)^2+15/77*(sin(1/2*d*x+1/2*c)^2)^(1/2 
)*(-2*cos(1/2*d*x+1/2*c)^2+1)^(1/2)/(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1 
/2*c)^2)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),2^(1/2)))+(1/16*B+1/4*C)*(-1/1 
44*cos(1/2*d*x+1/2*c)*(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/2) 
/(cos(1/2*d*x+1/2*c)^2-1/2)^5-7/180*cos(1/2*d*x+1/2*c)*(-2*sin(1/2*d*x+1/2 
*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/2)/(cos(1/2*d*x+1/2*c)^2-1/2)^3-14/15*sin(1 
/2*d*x+1/2*c)^2*cos(1/2*d*x+1/2*c)/(-(-2*cos(1/2*d*x+1/2*c)^2+1)*sin(1/2*d 
*x+1/2*c)^2)^(1/2)+7/15*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*cos(1/2*d*x+1/2*c 
)^2+1)^(1/2)/(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/2)*Elliptic 
F(cos(1/2*d*x+1/2*c),2^(1/2))-7/15*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*cos(1/ 
2*d*x+1/2*c)^2+1)^(1/2)/(-2*sin(1/2*d*x+1/2*c)^4+sin(1/2*d*x+1/2*c)^2)^(1/ 
2)*(EllipticF(cos(1/2*d*x+1/2*c),2^(1/2))-EllipticE(cos(1/2*d*x+1/2*c),2^( 
1/2))))+(1/4*A+1/16*B)/sin(1/2*d*x+1/2*c)^2/(2*sin(1/2*d*x+1/2*c)^2-1)*...
 
3.13.16.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.13 (sec) , antiderivative size = 327, normalized size of antiderivative = 1.05 \[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx=-\frac {2 \, {\left (30 i \, \sqrt {2} {\left (187 \, A + 132 \, B + 113 \, C\right )} a^{4} \cos \left (d x + c\right )^{6} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) - 30 i \, \sqrt {2} {\left (187 \, A + 132 \, B + 113 \, C\right )} a^{4} \cos \left (d x + c\right )^{6} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) + 462 i \, \sqrt {2} {\left (24 \, A + 19 \, B + 16 \, C\right )} a^{4} \cos \left (d x + c\right )^{6} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right )\right ) - 462 i \, \sqrt {2} {\left (24 \, A + 19 \, B + 16 \, C\right )} a^{4} \cos \left (d x + c\right )^{6} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right )\right ) - {\left (924 \, {\left (24 \, A + 19 \, B + 16 \, C\right )} a^{4} \cos \left (d x + c\right )^{5} + 15 \, {\left (517 \, A + 528 \, B + 452 \, C\right )} a^{4} \cos \left (d x + c\right )^{4} + 77 \, {\left (36 \, A + 61 \, B + 64 \, C\right )} a^{4} \cos \left (d x + c\right )^{3} + 45 \, {\left (11 \, A + 44 \, B + 75 \, C\right )} a^{4} \cos \left (d x + c\right )^{2} + 385 \, {\left (B + 4 \, C\right )} a^{4} \cos \left (d x + c\right ) + 315 \, C a^{4}\right )} \sqrt {\cos \left (d x + c\right )} \sin \left (d x + c\right )\right )}}{3465 \, d \cos \left (d x + c\right )^{6}} \]

input
integrate((a+a*sec(d*x+c))^4*(A+B*sec(d*x+c)+C*sec(d*x+c)^2)/cos(d*x+c)^(1 
/2),x, algorithm="fricas")
 
output
-2/3465*(30*I*sqrt(2)*(187*A + 132*B + 113*C)*a^4*cos(d*x + c)^6*weierstra 
ssPInverse(-4, 0, cos(d*x + c) + I*sin(d*x + c)) - 30*I*sqrt(2)*(187*A + 1 
32*B + 113*C)*a^4*cos(d*x + c)^6*weierstrassPInverse(-4, 0, cos(d*x + c) - 
 I*sin(d*x + c)) + 462*I*sqrt(2)*(24*A + 19*B + 16*C)*a^4*cos(d*x + c)^6*w 
eierstrassZeta(-4, 0, weierstrassPInverse(-4, 0, cos(d*x + c) + I*sin(d*x 
+ c))) - 462*I*sqrt(2)*(24*A + 19*B + 16*C)*a^4*cos(d*x + c)^6*weierstrass 
Zeta(-4, 0, weierstrassPInverse(-4, 0, cos(d*x + c) - I*sin(d*x + c))) - ( 
924*(24*A + 19*B + 16*C)*a^4*cos(d*x + c)^5 + 15*(517*A + 528*B + 452*C)*a 
^4*cos(d*x + c)^4 + 77*(36*A + 61*B + 64*C)*a^4*cos(d*x + c)^3 + 45*(11*A 
+ 44*B + 75*C)*a^4*cos(d*x + c)^2 + 385*(B + 4*C)*a^4*cos(d*x + c) + 315*C 
*a^4)*sqrt(cos(d*x + c))*sin(d*x + c))/(d*cos(d*x + c)^6)
 
3.13.16.6 Sympy [F(-1)]

Timed out. \[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx=\text {Timed out} \]

input
integrate((a+a*sec(d*x+c))**4*(A+B*sec(d*x+c)+C*sec(d*x+c)**2)/cos(d*x+c)* 
*(1/2),x)
 
output
Timed out
 
3.13.16.7 Maxima [F(-1)]

Timed out. \[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx=\text {Timed out} \]

input
integrate((a+a*sec(d*x+c))^4*(A+B*sec(d*x+c)+C*sec(d*x+c)^2)/cos(d*x+c)^(1 
/2),x, algorithm="maxima")
 
output
Timed out
 
3.13.16.8 Giac [F]

\[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx=\int { \frac {{\left (C \sec \left (d x + c\right )^{2} + B \sec \left (d x + c\right ) + A\right )} {\left (a \sec \left (d x + c\right ) + a\right )}^{4}}{\sqrt {\cos \left (d x + c\right )}} \,d x } \]

input
integrate((a+a*sec(d*x+c))^4*(A+B*sec(d*x+c)+C*sec(d*x+c)^2)/cos(d*x+c)^(1 
/2),x, algorithm="giac")
 
output
integrate((C*sec(d*x + c)^2 + B*sec(d*x + c) + A)*(a*sec(d*x + c) + a)^4/s 
qrt(cos(d*x + c)), x)
 
3.13.16.9 Mupad [B] (verification not implemented)

Time = 23.95 (sec) , antiderivative size = 830, normalized size of antiderivative = 2.68 \[ \int \frac {(a+a \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt {\cos (c+d x)}} \, dx=\text {Too large to display} \]

input
int(((a + a/cos(c + d*x))^4*(A + B/cos(c + d*x) + C/cos(c + d*x)^2))/cos(c 
 + d*x)^(1/2),x)
 
output
(8*((11*B*a^4*sin(c + d*x))/(cos(c + d*x)^(3/2)*(sin(c + d*x)^2)^(1/2)) + 
(3*B*a^4*sin(c + d*x))/(cos(c + d*x)^(7/2)*(sin(c + d*x)^2)^(1/2)))*hyperg 
eom([-3/4, 1/2], 1/4, cos(c + d*x)^2))/(21*d) - (8*((61*B*a^4*sin(c + d*x) 
)/(cos(c + d*x)^(1/2)*(sin(c + d*x)^2)^(1/2)) + (5*B*a^4*sin(c + d*x))/(co 
s(c + d*x)^(5/2)*(sin(c + d*x)^2)^(1/2)))*hypergeom([-1/4, 1/2], 7/4, cos( 
c + d*x)^2))/(135*d) + (8*((13*C*a^4*sin(c + d*x))/(cos(c + d*x)^(5/2)*(si 
n(c + d*x)^2)^(1/2)) + (5*C*a^4*sin(c + d*x))/(cos(c + d*x)^(9/2)*(sin(c + 
 d*x)^2)^(1/2)))*hypergeom([-5/4, 1/2], -1/4, cos(c + d*x)^2))/(45*d) + (8 
*((75*C*a^4*sin(c + d*x))/(cos(c + d*x)^(3/2)*(sin(c + d*x)^2)^(1/2)) + (7 
*C*a^4*sin(c + d*x))/(cos(c + d*x)^(7/2)*(sin(c + d*x)^2)^(1/2)))*hypergeo 
m([-3/4, 1/2], 5/4, cos(c + d*x)^2))/(231*d) + (2*hypergeom([-1/4, 1/2], 3 
/4, cos(c + d*x)^2)*((289*B*a^4*sin(c + d*x))/(cos(c + d*x)^(1/2)*(sin(c + 
 d*x)^2)^(1/2)) + (66*B*a^4*sin(c + d*x))/(cos(c + d*x)^(5/2)*(sin(c + d*x 
)^2)^(1/2)) + (5*B*a^4*sin(c + d*x))/(cos(c + d*x)^(9/2)*(sin(c + d*x)^2)^ 
(1/2))))/(45*d) + (2*hypergeom([-3/4, 1/2], 1/4, cos(c + d*x)^2)*((377*C*a 
^4*sin(c + d*x))/(cos(c + d*x)^(3/2)*(sin(c + d*x)^2)^(1/2)) + (218*C*a^4* 
sin(c + d*x))/(cos(c + d*x)^(7/2)*(sin(c + d*x)^2)^(1/2)) + (21*C*a^4*sin( 
c + d*x))/(cos(c + d*x)^(11/2)*(sin(c + d*x)^2)^(1/2))))/(231*d) + (2*A*a^ 
4*ellipticF(c/2 + (d*x)/2, 2))/d + (8*A*a^4*sin(c + d*x)*hypergeom([-1/4, 
1/2], 3/4, cos(c + d*x)^2))/(d*cos(c + d*x)^(1/2)*(sin(c + d*x)^2)^(1/2...